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A surface of revolution is a threedimensional surface with circular cross sections, like a vase or a bell or a wine bottle For these problems, you divide the surface into narrow circular bands, figure the surface area of a representative band, and then just add up the areas of all the bands to get theCos θ as `"adj"/"hyp"`, and tan θ as `"opp"/"adj"`, but we are using the specific x, y and rvalues defined by the point (x, y) that the terminal side passes throughSo the circle is all the points (x,y) that are "r" away from the center (a,b) Now lets work out where the points are (using a rightangled triangle and Pythagoras) It is the same idea as before, but we need to subtract a and b (x−a) 2 (y−b) 2 = r 2
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In most R regression packages, y ~ 1 means "fit an intercept only " So in the case of linear regression, this is exactly the same as mean (y) For glm's, it depends on the link function Also, y ~ x 1 means "regress x on y, but leave out the intercept" ShareY 1 =2X 1,Y 2 = X 2 −X 1 Find the joint density of Y 1 and Y 2,and conclude thatY 1 and Y 2 are independent 2 Repeat Problem 1 with the following new data The joint density is given by f(x 1,x 2)= 8x 1x 2, 0Thereform r 0 In diagram (c), the x and yvariables have no relationship The positive products in quadrants I and III cancel out the negative products in quadrants II and VI so the average of the products is close to 0;
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